2(3t-1)=10-4(t+3)

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Solution for 2(3t-1)=10-4(t+3) equation: 



2(3t-1)=10-4(t+3)

We move all terms to the left:

2(3t-1)-(10-4(t+3))=0

We multiply parentheses

6t-(10-4(t+3))-2=0



We calculate terms in parentheses: -(10-4(t+3)), so:

10-4(t+3)

determiningTheFunctionDomain
-4(t+3)+10

We multiply parentheses

-4t-12+10

We add all the numbers together, and all the variables

-4t-2

Back to the equation:

-(-4t-2)



We get rid of parentheses

6t+4t+2-2=0

We add all the numbers together, and all the variables

10t=0

t=0/10

t=0

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