2(3r-4)+r-1=-16

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Solution for 2(3r-4)+r-1=-16 equation: 



2(3r-4)+r-1=-16

We move all terms to the left:

2(3r-4)+r-1-(-16)=0

We add all the numbers together, and all the variables

r+2(3r-4)+15=0

We multiply parentheses

r+6r-8+15=0

We add all the numbers together, and all the variables

7r+7=0

We move all terms containing r to the left, all other terms to the right

7r=-7

r=-7/7

r=-1

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