2(3r+4)=-20-r

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Solution for 2(3r+4)=-20-r equation: 



2(3r+4)=-20-r

We move all terms to the left:

2(3r+4)-(-20-r)=0

We add all the numbers together, and all the variables

2(3r+4)-(-1r-20)=0

We multiply parentheses

6r-(-1r-20)+8=0

We get rid of parentheses

6r+1r+20+8=0

We add all the numbers together, and all the variables

7r+28=0

We move all terms containing r to the left, all other terms to the right

7r=-28

r=-28/7

r=-4

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