2(3r+4)3r(r+1)=11

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Solution for 2(3r+4)3r(r+1)=11 equation:


Simplifying
2(3r + 4) * 3r(r + 1) = 11

Reorder the terms:
2(4 + 3r) * 3r(r + 1) = 11

Reorder the terms:
2(4 + 3r) * 3r(1 + r) = 11

Reorder the terms for easier multiplication:
2 * 3r(4 + 3r)(1 + r) = 11

Multiply 2 * 3
6r(4 + 3r)(1 + r) = 11

Multiply (4 + 3r) * (1 + r)
6r(4(1 + r) + 3r * (1 + r)) = 11
6r((1 * 4 + r * 4) + 3r * (1 + r)) = 11
6r((4 + 4r) + 3r * (1 + r)) = 11
6r(4 + 4r + (1 * 3r + r * 3r)) = 11
6r(4 + 4r + (3r + 3r2)) = 11

Combine like terms: 4r + 3r = 7r
6r(4 + 7r + 3r2) = 11
(4 * 6r + 7r * 6r + 3r2 * 6r) = 11
(24r + 42r2 + 18r3) = 11

Solving
24r + 42r2 + 18r3 = 11

Solving for variable 'r'.

Reorder the terms:
-11 + 24r + 42r2 + 18r3 = 11 + -11

Combine like terms: 11 + -11 = 0
-11 + 24r + 42r2 + 18r3 = 0

The solution to this equation could not be determined.

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