2(3r+1)+6=5(-2r-8)

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Solution for 2(3r+1)+6=5(-2r-8) equation:


Simplifying
2(3r + 1) + 6 = 5(-2r + -8)

Reorder the terms:
2(1 + 3r) + 6 = 5(-2r + -8)
(1 * 2 + 3r * 2) + 6 = 5(-2r + -8)
(2 + 6r) + 6 = 5(-2r + -8)

Reorder the terms:
2 + 6 + 6r = 5(-2r + -8)

Combine like terms: 2 + 6 = 8
8 + 6r = 5(-2r + -8)

Reorder the terms:
8 + 6r = 5(-8 + -2r)
8 + 6r = (-8 * 5 + -2r * 5)
8 + 6r = (-40 + -10r)

Solving
8 + 6r = -40 + -10r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '10r' to each side of the equation.
8 + 6r + 10r = -40 + -10r + 10r

Combine like terms: 6r + 10r = 16r
8 + 16r = -40 + -10r + 10r

Combine like terms: -10r + 10r = 0
8 + 16r = -40 + 0
8 + 16r = -40

Add '-8' to each side of the equation.
8 + -8 + 16r = -40 + -8

Combine like terms: 8 + -8 = 0
0 + 16r = -40 + -8
16r = -40 + -8

Combine like terms: -40 + -8 = -48
16r = -48

Divide each side by '16'.
r = -3

Simplifying
r = -3

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