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2(3q-3)=2(2q+3)
We move all terms to the left:
2(3q-3)-(2(2q+3))=0
We multiply parentheses
6q-(2(2q+3))-6=0
We calculate terms in parentheses: -(2(2q+3)), so:We get rid of parentheses
2(2q+3)
We multiply parentheses
4q+6
Back to the equation:
-(4q+6)
6q-4q-6-6=0
We add all the numbers together, and all the variables
2q-12=0
We move all terms containing q to the left, all other terms to the right
2q=12
q=12/2
q=6
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