2(3q-1)+4(q+5)=58

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Solution for 2(3q-1)+4(q+5)=58 equation: 


Simplifying
2(3q + -1) + 4(q + 5) = 58

Reorder the terms:
2(-1 + 3q) + 4(q + 5) = 58
(-1 * 2 + 3q * 2) + 4(q + 5) = 58
(-2 + 6q) + 4(q + 5) = 58

Reorder the terms:
-2 + 6q + 4(5 + q) = 58
-2 + 6q + (5 * 4 + q * 4) = 58
-2 + 6q + (20 + 4q) = 58

Reorder the terms:
-2 + 20 + 6q + 4q = 58

Combine like terms: -2 + 20 = 18
18 + 6q + 4q = 58

Combine like terms: 6q + 4q = 10q
18 + 10q = 58

Solving
18 + 10q = 58

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + 10q = 58 + -18

Combine like terms: 18 + -18 = 0
0 + 10q = 58 + -18
10q = 58 + -18

Combine like terms: 58 + -18 = 40
10q = 40

Divide each side by '10'.
q = 4

Simplifying
q = 4

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