2(3p-2)+1=3(p+3)

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Solution for 2(3p-2)+1=3(p+3) equation:



2(3p-2)+1=3(p+3)
We move all terms to the left:
2(3p-2)+1-(3(p+3))=0
We multiply parentheses
6p-(3(p+3))-4+1=0
We calculate terms in parentheses: -(3(p+3)), so:
3(p+3)
We multiply parentheses
3p+9
Back to the equation:
-(3p+9)
We add all the numbers together, and all the variables
6p-(3p+9)-3=0
We get rid of parentheses
6p-3p-9-3=0
We add all the numbers together, and all the variables
3p-12=0
We move all terms containing p to the left, all other terms to the right
3p=12
p=12/3
p=4

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