2(3n-4)=-2(n-2)

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Solution for 2(3n-4)=-2(n-2) equation: 



2(3n-4)=-2(n-2)

We move all terms to the left:

2(3n-4)-(-2(n-2))=0

We multiply parentheses

6n-(-2(n-2))-8=0



We calculate terms in parentheses: -(-2(n-2)), so:

-2(n-2)

We multiply parentheses

-2n+4

Back to the equation:

-(-2n+4)



We get rid of parentheses

6n+2n-4-8=0

We add all the numbers together, and all the variables

8n-12=0

We move all terms containing n to the left, all other terms to the right

8n=12

n=12/8

n=1+1/2

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