2(3n+1)=7(9n+3)+5

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Solution for 2(3n+1)=7(9n+3)+5 equation: 



2(3n+1)=7(9n+3)+5

We move all terms to the left:

2(3n+1)-(7(9n+3)+5)=0

We multiply parentheses

6n-(7(9n+3)+5)+2=0



We calculate terms in parentheses: -(7(9n+3)+5), so:

7(9n+3)+5

We multiply parentheses

63n+21+5

We add all the numbers together, and all the variables

63n+26

Back to the equation:

-(63n+26)



We get rid of parentheses

6n-63n-26+2=0

We add all the numbers together, and all the variables

-57n-24=0

We move all terms containing n to the left, all other terms to the right

-57n=24

n=24/-57

n=-8/19

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