2(3n+1)=-4(n-3)

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Solution for 2(3n+1)=-4(n-3) equation: 



2(3n+1)=-4(n-3)

We move all terms to the left:

2(3n+1)-(-4(n-3))=0

We multiply parentheses

6n-(-4(n-3))+2=0



We calculate terms in parentheses: -(-4(n-3)), so:

-4(n-3)

We multiply parentheses

-4n+12

Back to the equation:

-(-4n+12)



We get rid of parentheses

6n+4n-12+2=0

We add all the numbers together, and all the variables

10n-10=0

We move all terms containing n to the left, all other terms to the right

10n=10

n=10/10

n=1

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