2(3m-5)-4(2+m)=3(m-6)

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Solution for 2(3m-5)-4(2+m)=3(m-6) equation: 



2(3m-5)-4(2+m)=3(m-6)

We move all terms to the left:

2(3m-5)-4(2+m)-(3(m-6))=0

We add all the numbers together, and all the variables

2(3m-5)-4(m+2)-(3(m-6))=0

We multiply parentheses

6m-4m-(3(m-6))-10-8=0



We calculate terms in parentheses: -(3(m-6)), so:

3(m-6)

We multiply parentheses

3m-18

Back to the equation:

-(3m-18)



We add all the numbers together, and all the variables

2m-(3m-18)-18=0

We get rid of parentheses

2m-3m+18-18=0

We add all the numbers together, and all the variables

-m=0

m=0/-1

m=0

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