2(3m-4)=2(m+12)+4m-1

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Solution for 2(3m-4)=2(m+12)+4m-1 equation: 



2(3m-4)=2(m+12)+4m-1

We move all terms to the left:

2(3m-4)-(2(m+12)+4m-1)=0

We multiply parentheses

6m-(2(m+12)+4m-1)-8=0



We calculate terms in parentheses: -(2(m+12)+4m-1), so:

2(m+12)+4m-1

We add all the numbers together, and all the variables

4m+2(m+12)-1

We multiply parentheses

4m+2m+24-1

We add all the numbers together, and all the variables

6m+23

Back to the equation:

-(6m+23)



We get rid of parentheses

6m-6m-23-8=0

We add all the numbers together, and all the variables

-31!=0

There is no solution for this equation

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