2(3m+2)=4m+20

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Solution for 2(3m+2)=4m+20 equation: 



2(3m+2)=4m+20

We move all terms to the left:

2(3m+2)-(4m+20)=0

We multiply parentheses

6m-(4m+20)+4=0

We get rid of parentheses

6m-4m-20+4=0

We add all the numbers together, and all the variables

2m-16=0

We move all terms containing m to the left, all other terms to the right

2m=16

m=16/2

m=8

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