2(3k-2)=8-(2k+6)

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Solution for 2(3k-2)=8-(2k+6) equation:



2(3k-2)=8-(2k+6)
We move all terms to the left:
2(3k-2)-(8-(2k+6))=0
We multiply parentheses
6k-(8-(2k+6))-4=0
We calculate terms in parentheses: -(8-(2k+6)), so:
8-(2k+6)
determiningTheFunctionDomain -(2k+6)+8
We get rid of parentheses
-2k-6+8
We add all the numbers together, and all the variables
-2k+2
Back to the equation:
-(-2k+2)
We get rid of parentheses
6k+2k-2-4=0
We add all the numbers together, and all the variables
8k-6=0
We move all terms containing k to the left, all other terms to the right
8k=6
k=6/8
k=3/4

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