2(3k+5)=9k-3(k+4)-1

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Solution for 2(3k+5)=9k-3(k+4)-1 equation: 



2(3k+5)=9k-3(k+4)-1

We move all terms to the left:

2(3k+5)-(9k-3(k+4)-1)=0

We multiply parentheses

6k-(9k-3(k+4)-1)+10=0



We calculate terms in parentheses: -(9k-3(k+4)-1), so:

9k-3(k+4)-1

We multiply parentheses

9k-3k-12-1

We add all the numbers together, and all the variables

6k-13

Back to the equation:

-(6k-13)



We get rid of parentheses

6k-6k+13+10=0

We add all the numbers together, and all the variables

23!=0

There is no solution for this equation

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