2(3k+4)=-2k+4(k-7)

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Solution for 2(3k+4)=-2k+4(k-7) equation: 



2(3k+4)=-2k+4(k-7)

We move all terms to the left:

2(3k+4)-(-2k+4(k-7))=0

We multiply parentheses

6k-(-2k+4(k-7))+8=0



We calculate terms in parentheses: -(-2k+4(k-7)), so:

-2k+4(k-7)

We multiply parentheses

-2k+4k-28

We add all the numbers together, and all the variables

2k-28

Back to the equation:

-(2k-28)



We get rid of parentheses

6k-2k+28+8=0

We add all the numbers together, and all the variables

4k+36=0

We move all terms containing k to the left, all other terms to the right

4k=-36

k=-36/4

k=-9

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