2(3f+5)=28

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Solution for 2(3f+5)=28 equation: 


Simplifying
2(3f + 5) = 28

Reorder the terms:
2(5 + 3f) = 28
(5 * 2 + 3f * 2) = 28
(10 + 6f) = 28

Solving
10 + 6f = 28

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 6f = 28 + -10

Combine like terms: 10 + -10 = 0
0 + 6f = 28 + -10
6f = 28 + -10

Combine like terms: 28 + -10 = 18
6f = 18

Divide each side by '6'.
f = 3

Simplifying
f = 3

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