2(3f+12)=40

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Solution for 2(3f+12)=40 equation:



2(3f+12)=40
We move all terms to the left:
2(3f+12)-(40)=0
We multiply parentheses
6f+24-40=0
We add all the numbers together, and all the variables
6f-16=0
We move all terms containing f to the left, all other terms to the right
6f=16
f=16/6
f=2+2/3

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