2(3d+3)=3(3d+1)

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Solution for 2(3d+3)=3(3d+1) equation: 



2(3d+3)=3(3d+1)

We move all terms to the left:

2(3d+3)-(3(3d+1))=0

We multiply parentheses

6d-(3(3d+1))+6=0



We calculate terms in parentheses: -(3(3d+1)), so:

3(3d+1)

We multiply parentheses

9d+3

Back to the equation:

-(9d+3)



We get rid of parentheses

6d-9d-3+6=0

We add all the numbers together, and all the variables

-3d+3=0

We move all terms containing d to the left, all other terms to the right

-3d=-3

d=-3/-3

d=1

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