2(3c-6)=3(3c+2)

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Solution for 2(3c-6)=3(3c+2) equation: 



2(3c-6)=3(3c+2)

We move all terms to the left:

2(3c-6)-(3(3c+2))=0

We multiply parentheses

6c-(3(3c+2))-12=0



We calculate terms in parentheses: -(3(3c+2)), so:

3(3c+2)

We multiply parentheses

9c+6

Back to the equation:

-(9c+6)



We get rid of parentheses

6c-9c-6-12=0

We add all the numbers together, and all the variables

-3c-18=0

We move all terms containing c to the left, all other terms to the right

-3c=18

c=18/-3

c=-6

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