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2(3c-6)-2c=4(c+4)
We move all terms to the left:
2(3c-6)-2c-(4(c+4))=0
We add all the numbers together, and all the variables
-2c+2(3c-6)-(4(c+4))=0
We multiply parentheses
-2c+6c-(4(c+4))-12=0
We calculate terms in parentheses: -(4(c+4)), so:We add all the numbers together, and all the variables
4(c+4)
We multiply parentheses
4c+16
Back to the equation:
-(4c+16)
4c-(4c+16)-12=0
We get rid of parentheses
4c-4c-16-12=0
We add all the numbers together, and all the variables
-28!=0
There is no solution for this equation
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