2(3c-5)=4(c+7)

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Solution for 2(3c-5)=4(c+7) equation: 



2(3c-5)=4(c+7)

We move all terms to the left:

2(3c-5)-(4(c+7))=0

We multiply parentheses

6c-(4(c+7))-10=0



We calculate terms in parentheses: -(4(c+7)), so:

4(c+7)

We multiply parentheses

4c+28

Back to the equation:

-(4c+28)



We get rid of parentheses

6c-4c-28-10=0

We add all the numbers together, and all the variables

2c-38=0

We move all terms containing c to the left, all other terms to the right

2c=38

c=38/2

c=19

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