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2(3c-5)-(c+2)=5c-12
We move all terms to the left:
2(3c-5)-(c+2)-(5c-12)=0
We multiply parentheses
6c-(c+2)-(5c-12)-10=0
We get rid of parentheses
6c-c-5c-2+12-10=0
We add all the numbers together, and all the variables
=0
c=0/1
c=0
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