2(3c-4)-5(2c+1)=4(2c+6)

Solution for 2(3c-4)-5(2c+1)=4(2c+6) equation:

2(3c-4)-5(2c+1)=4(2c+6)

We move all terms to the left:

2(3c-4)-5(2c+1)-(4(2c+6))=0

We multiply parentheses

6c-10c-(4(2c+6))-8-5=0


We calculate terms in parentheses: -(4(2c+6)), so:

4(2c+6)

We multiply parentheses

8c+24

Back to the equation:

-(8c+24)


We add all the numbers together, and all the variables

-4c-(8c+24)-13=0

We get rid of parentheses

-4c-8c-24-13=0

We add all the numbers together, and all the variables

-12c-37=0

We move all terms containing c to the left, all other terms to the right

-12c=37

c=37/-12

c=-3+1/12