2(3c-3)-4(3)+2(5c-7)=0

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Solution for 2(3c-3)-4(3)+2(5c-7)=0 equation:


Simplifying
2(3c + -3) + -4(3) + 2(5c + -7) = 0

Reorder the terms:
2(-3 + 3c) + -4(3) + 2(5c + -7) = 0
(-3 * 2 + 3c * 2) + -4(3) + 2(5c + -7) = 0
(-6 + 6c) + -4(3) + 2(5c + -7) = 0

Multiply -4 * 3
-6 + 6c + -12 + 2(5c + -7) = 0

Reorder the terms:
-6 + 6c + -12 + 2(-7 + 5c) = 0
-6 + 6c + -12 + (-7 * 2 + 5c * 2) = 0
-6 + 6c + -12 + (-14 + 10c) = 0

Reorder the terms:
-6 + -12 + -14 + 6c + 10c = 0

Combine like terms: -6 + -12 = -18
-18 + -14 + 6c + 10c = 0

Combine like terms: -18 + -14 = -32
-32 + 6c + 10c = 0

Combine like terms: 6c + 10c = 16c
-32 + 16c = 0

Solving
-32 + 16c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '32' to each side of the equation.
-32 + 32 + 16c = 0 + 32

Combine like terms: -32 + 32 = 0
0 + 16c = 0 + 32
16c = 0 + 32

Combine like terms: 0 + 32 = 32
16c = 32

Divide each side by '16'.
c = 2

Simplifying
c = 2

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