2(3c-1)1=2c+5

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Solution for 2(3c-1)1=2c+5 equation:


Simplifying
2(3c + -1) * 1 = 2c + 5

Reorder the terms:
2(-1 + 3c) * 1 = 2c + 5

Reorder the terms for easier multiplication:
2 * 1(-1 + 3c) = 2c + 5

Multiply 2 * 1
2(-1 + 3c) = 2c + 5
(-1 * 2 + 3c * 2) = 2c + 5
(-2 + 6c) = 2c + 5

Reorder the terms:
-2 + 6c = 5 + 2c

Solving
-2 + 6c = 5 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-2 + 6c + -2c = 5 + 2c + -2c

Combine like terms: 6c + -2c = 4c
-2 + 4c = 5 + 2c + -2c

Combine like terms: 2c + -2c = 0
-2 + 4c = 5 + 0
-2 + 4c = 5

Add '2' to each side of the equation.
-2 + 2 + 4c = 5 + 2

Combine like terms: -2 + 2 = 0
0 + 4c = 5 + 2
4c = 5 + 2

Combine like terms: 5 + 2 = 7
4c = 7

Divide each side by '4'.
c = 1.75

Simplifying
c = 1.75

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