2(3c+7)=4(4c+1)

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Solution for 2(3c+7)=4(4c+1) equation:


Simplifying
2(3c + 7) = 4(4c + 1)

Reorder the terms:
2(7 + 3c) = 4(4c + 1)
(7 * 2 + 3c * 2) = 4(4c + 1)
(14 + 6c) = 4(4c + 1)

Reorder the terms:
14 + 6c = 4(1 + 4c)
14 + 6c = (1 * 4 + 4c * 4)
14 + 6c = (4 + 16c)

Solving
14 + 6c = 4 + 16c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-16c' to each side of the equation.
14 + 6c + -16c = 4 + 16c + -16c

Combine like terms: 6c + -16c = -10c
14 + -10c = 4 + 16c + -16c

Combine like terms: 16c + -16c = 0
14 + -10c = 4 + 0
14 + -10c = 4

Add '-14' to each side of the equation.
14 + -14 + -10c = 4 + -14

Combine like terms: 14 + -14 = 0
0 + -10c = 4 + -14
-10c = 4 + -14

Combine like terms: 4 + -14 = -10
-10c = -10

Divide each side by '-10'.
c = 1

Simplifying
c = 1

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