2(3c+3)=3(2c+2)

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Solution for 2(3c+3)=3(2c+2) equation: 



2(3c+3)=3(2c+2)

We move all terms to the left:

2(3c+3)-(3(2c+2))=0

We multiply parentheses

6c-(3(2c+2))+6=0



We calculate terms in parentheses: -(3(2c+2)), so:

3(2c+2)

We multiply parentheses

6c+6

Back to the equation:

-(6c+6)



We get rid of parentheses

6c-6c-6+6=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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