2(3c+2)=1/2(12c-6)-1

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Solution for 2(3c+2)=1/2(12c-6)-1 equation: 



2(3c+2)=1/2(12c-6)-1

We move all terms to the left:

2(3c+2)-(1/2(12c-6)-1)=0



Domain of the equation: 2(12c-6)-1)!=0

c∈R



We multiply parentheses

6c-(1/2(12c-6)-1)+4=0

We multiply all the terms by the denominator


6c*2(12c-6)+4*2(12c-6)-1)-(1-1)=0

We add all the numbers together, and all the variables

6c*2(12c-6)+4*2(12c-6)-1)-0=0

We add all the numbers together, and all the variables

6c*2(12c-6)+4*2(12c-6)=0

Wy multiply elements

12c^2(1+8c(1=0

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