2(3b-10)=b-50

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Solution for 2(3b-10)=b-50 equation:


Simplifying
2(3b + -10) = b + -50

Reorder the terms:
2(-10 + 3b) = b + -50
(-10 * 2 + 3b * 2) = b + -50
(-20 + 6b) = b + -50

Reorder the terms:
-20 + 6b = -50 + b

Solving
-20 + 6b = -50 + b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
-20 + 6b + -1b = -50 + b + -1b

Combine like terms: 6b + -1b = 5b
-20 + 5b = -50 + b + -1b

Combine like terms: b + -1b = 0
-20 + 5b = -50 + 0
-20 + 5b = -50

Add '20' to each side of the equation.
-20 + 20 + 5b = -50 + 20

Combine like terms: -20 + 20 = 0
0 + 5b = -50 + 20
5b = -50 + 20

Combine like terms: -50 + 20 = -30
5b = -30

Divide each side by '5'.
b = -6

Simplifying
b = -6

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