2(3b+4)-3(4-b)=6b+8-12+3b

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Solution for 2(3b+4)-3(4-b)=6b+8-12+3b equation: 



2(3b+4)-3(4-b)=6b+8-12+3b

We move all terms to the left:

2(3b+4)-3(4-b)-(6b+8-12+3b)=0

We add all the numbers together, and all the variables

2(3b+4)-3(-1b+4)-(9b-4)=0

We multiply parentheses

6b+3b-(9b-4)+8-12=0

We get rid of parentheses

6b+3b-9b+4+8-12=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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