2(3a+4)+4(4a-5)=10

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Solution for 2(3a+4)+4(4a-5)=10 equation: 



2(3a+4)+4(4a-5)=10

We move all terms to the left:

2(3a+4)+4(4a-5)-(10)=0

We multiply parentheses

6a+16a+8-20-10=0

We add all the numbers together, and all the variables

22a-22=0

We move all terms containing a to the left, all other terms to the right

22a=22

a=22/22

a=1

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