2(3a+2)=3(a-1)

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Solution for 2(3a+2)=3(a-1) equation: 



2(3a+2)=3(a-1)

We move all terms to the left:

2(3a+2)-(3(a-1))=0

We multiply parentheses

6a-(3(a-1))+4=0



We calculate terms in parentheses: -(3(a-1)), so:

3(a-1)

We multiply parentheses

3a-3

Back to the equation:

-(3a-3)



We get rid of parentheses

6a-3a+3+4=0

We add all the numbers together, and all the variables

3a+7=0

We move all terms containing a to the left, all other terms to the right

3a=-7

a=-7/3

a=-2+1/3

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