2(3a+2)-(3a+5)+3=12+3(2a-1)-2a

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Solution for 2(3a+2)-(3a+5)+3=12+3(2a-1)-2a equation: 



2(3a+2)-(3a+5)+3=12+3(2a-1)-2a

We move all terms to the left:

2(3a+2)-(3a+5)+3-(12+3(2a-1)-2a)=0

We multiply parentheses

6a-(3a+5)-(12+3(2a-1)-2a)+4+3=0

We get rid of parentheses

6a-3a-(12+3(2a-1)-2a)-5+4+3=0



We calculate terms in parentheses: -(12+3(2a-1)-2a), so:

12+3(2a-1)-2a

determiningTheFunctionDomain
3(2a-1)-2a+12

We add all the numbers together, and all the variables

-2a+3(2a-1)+12

We multiply parentheses

-2a+6a-3+12

We add all the numbers together, and all the variables

4a+9

Back to the equation:

-(4a+9)



We add all the numbers together, and all the variables

3a-(4a+9)+2=0

We get rid of parentheses

3a-4a-9+2=0

We add all the numbers together, and all the variables

-1a-7=0

We move all terms containing a to the left, all other terms to the right

-a=7

a=7/-1

a=-7

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