2(3D+2)=14+6s

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Solution for 2(3D+2)=14+6s equation: 



2(3+2)=14+6D

We move all terms to the left:

2(3+2)-(14+6D)=0

We add all the numbers together, and all the variables

-(6D+14)+25=0

We get rid of parentheses

-6D-14+25=0

We add all the numbers together, and all the variables

-6D+11=0

We move all terms containing D to the left, all other terms to the right

-6D=-11

D=-11/-6

D=1+5/6

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