2(35-y)+4y=110

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Solution for 2(35-y)+4y=110 equation: 



2(35-y)+4y=110

We move all terms to the left:

2(35-y)+4y-(110)=0

We add all the numbers together, and all the variables

2(-1y+35)+4y-110=0

We add all the numbers together, and all the variables

4y+2(-1y+35)-110=0

We multiply parentheses

4y-2y+70-110=0

We add all the numbers together, and all the variables

2y-40=0

We move all terms containing y to the left, all other terms to the right

2y=40

y=40/2

y=20

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