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2(3/2x-4)+x=2
We move all terms to the left:
2(3/2x-4)+x-(2)=0
Domain of the equation: 2x-4)!=0We add all the numbers together, and all the variables
x∈R
x+2(3/2x-4)-2=0
We multiply parentheses
x+6x-8-2=0
We add all the numbers together, and all the variables
7x-10=0
We move all terms containing x to the left, all other terms to the right
7x=10
x=10/7
x=1+3/7
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