2(3-z)+4(2z-6)=30

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Solution for 2(3-z)+4(2z-6)=30 equation: 



2(3-z)+4(2z-6)=30

We move all terms to the left:

2(3-z)+4(2z-6)-(30)=0

We add all the numbers together, and all the variables

2(-1z+3)+4(2z-6)-30=0

We multiply parentheses

-2z+8z+6-24-30=0

We add all the numbers together, and all the variables

6z-48=0

We move all terms containing z to the left, all other terms to the right

6z=48

z=48/6

z=8

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