2(3-x)=3(x+3)+2

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Solution for 2(3-x)=3(x+3)+2 equation: 



2(3-x)=3(x+3)+2

We move all terms to the left:

2(3-x)-(3(x+3)+2)=0

We add all the numbers together, and all the variables

2(-1x+3)-(3(x+3)+2)=0

We multiply parentheses

-2x-(3(x+3)+2)+6=0



We calculate terms in parentheses: -(3(x+3)+2), so:

3(x+3)+2

We multiply parentheses

3x+9+2

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We get rid of parentheses

-2x-3x-11+6=0

We add all the numbers together, and all the variables

-5x-5=0

We move all terms containing x to the left, all other terms to the right

-5x=5

x=5/-5

x=-1

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