2(3-x)=(1/2)(4x-2)

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Solution for 2(3-x)=(1/2)(4x-2) equation: 



2(3-x)=(1/2)(4x-2)

We move all terms to the left:

2(3-x)-((1/2)(4x-2))=0



Domain of the equation: 2)(4x-2))!=0

x∈R



We add all the numbers together, and all the variables

2(-1x+3)-((+1/2)(4x-2))=0

We multiply parentheses

-2x-((+1/2)(4x-2))+6=0

We multiply parentheses ..

-((+4x^2+1/2*-2))-2x+6=0

We multiply all the terms by the denominator


-((+4x^2+1-2x*2*-2))+6*2*-2))=0



We calculate terms in parentheses: -((+4x^2+1-2x*2*-2)), so:

(+4x^2+1-2x*2*-2)

We get rid of parentheses

4x^2-2x*2*+1-2

We add all the numbers together, and all the variables

4x^2-2x*2*-1

Wy multiply elements

4x^2-4x^2-1

We add all the numbers together, and all the variables

-1

Back to the equation:

-(-1)



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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