2(3-6x)-5(3-(4-2x))=3(2x-1)

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Solution for 2(3-6x)-5(3-(4-2x))=3(2x-1) equation: 



2(3-6x)-5(3-(4-2x))=3(2x-1)

We move all terms to the left:

2(3-6x)-5(3-(4-2x))-(3(2x-1))=0

We add all the numbers together, and all the variables

2(-6x+3)-5(3-(-2x+4))-(3(2x-1))=0

We multiply parentheses

-12x-5(3-(-2x+4))-(3(2x-1))+6=0



We calculate terms in parentheses: -(3(2x-1)), so:

3(2x-1)

We multiply parentheses

6x-3

Back to the equation:

-(6x-3)



We get rid of parentheses

-12x-5(3-(-2x+4))-6x+3+6=0

We add all the numbers together, and all the variables

-18x-5(3-(-2x+4))+9=0

We move all terms containing x to the left, all other terms to the right

-18x-5(3-(-2x+4))=-9

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