2(3-4b)=60-2b-3(3b-11)

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Solution for 2(3-4b)=60-2b-3(3b-11) equation: 



2(3-4b)=60-2b-3(3b-11)

We move all terms to the left:

2(3-4b)-(60-2b-3(3b-11))=0

We add all the numbers together, and all the variables

2(-4b+3)-(60-2b-3(3b-11))=0

We multiply parentheses

-8b-(60-2b-3(3b-11))+6=0



We calculate terms in parentheses: -(60-2b-3(3b-11)), so:

60-2b-3(3b-11)

determiningTheFunctionDomain
-2b-3(3b-11)+60

We multiply parentheses

-2b-9b+33+60

We add all the numbers together, and all the variables

-11b+93

Back to the equation:

-(-11b+93)



We get rid of parentheses

-8b+11b-93+6=0

We add all the numbers together, and all the variables

3b-87=0

We move all terms containing b to the left, all other terms to the right

3b=87

b=87/3

b=29

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