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2(3-2x)=2(2x+5)
We move all terms to the left:
2(3-2x)-(2(2x+5))=0
We add all the numbers together, and all the variables
2(-2x+3)-(2(2x+5))=0
We multiply parentheses
-4x-(2(2x+5))+6=0
We calculate terms in parentheses: -(2(2x+5)), so:We get rid of parentheses
2(2x+5)
We multiply parentheses
4x+10
Back to the equation:
-(4x+10)
-4x-4x-10+6=0
We add all the numbers together, and all the variables
-8x-4=0
We move all terms containing x to the left, all other terms to the right
-8x=4
x=4/-8
x=-1/2
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