2(3-2r)=3(2r-0)

Solution for 2(3-2r)=3(2r-0) equation:

Simplifying
2(3 + -2r) = 3(2r + 0)
(3 * 2 + -2r * 2) = 3(2r + 0)
(6 + -4r) = 3(2r + 0)

Reorder the terms:
6 + -4r = 3(0 + 2r)
Remove the zero:
6 + -4r = 3(2r)

Remove parenthesis around (2r)
6 + -4r = 3 * 2r

Multiply 3 * 2
6 + -4r = 6r

Solving
6 + -4r = 6r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-6r' to each side of the equation.
6 + -4r + -6r = 6r + -6r

Combine like terms: -4r + -6r = -10r
6 + -10r = 6r + -6r

Combine like terms: 6r + -6r = 0
6 + -10r = 0

Add '-6' to each side of the equation.
6 + -6 + -10r = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -10r = 0 + -6
-10r = 0 + -6

Combine like terms: 0 + -6 = -6
-10r = -6

Divide each side by '-10'.
r = 0.6

Simplifying
r = 0.6