2(3-2X)=3(2x+3)

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Solution for 2(3-2X)=3(2x+3) equation: 



2(3-2X)=3(2X+3)

We move all terms to the left:

2(3-2X)-(3(2X+3))=0

We add all the numbers together, and all the variables

2(-2X+3)-(3(2X+3))=0

We multiply parentheses

-4X-(3(2X+3))+6=0



We calculate terms in parentheses: -(3(2X+3)), so:

3(2X+3)

We multiply parentheses

6X+9

Back to the equation:

-(6X+9)



We get rid of parentheses

-4X-6X-9+6=0

We add all the numbers together, and all the variables

-10X-3=0

We move all terms containing X to the left, all other terms to the right

-10X=3

X=3/-10

X=-3/10

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