2(3+x)=4(x+1)

Solution for 2(3+x)=4(x+1) equation:

2(3+x)=4(x+1)

We move all terms to the left:

2(3+x)-(4(x+1))=0

We add all the numbers together, and all the variables

2(x+3)-(4(x+1))=0

We multiply parentheses

2x-(4(x+1))+6=0


We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)


We get rid of parentheses

2x-4x-4+6=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1