2(3+5j)=(2j-2)

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Solution for 2(3+5j)=(2j-2) equation: 



2(3+5j)=(2j-2)

We move all terms to the left:

2(3+5j)-((2j-2))=0

We add all the numbers together, and all the variables

2(5j+3)-((2j-2))=0

We multiply parentheses

10j-((2j-2))+6=0



We calculate terms in parentheses: -((2j-2)), so:

(2j-2)

We get rid of parentheses

2j-2

Back to the equation:

-(2j-2)



We get rid of parentheses

10j-2j+2+6=0

We add all the numbers together, and all the variables

8j+8=0

We move all terms containing j to the left, all other terms to the right

8j=-8

j=-8/8

j=-1

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