2(3+4x)=7(x-5)

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Solution for 2(3+4x)=7(x-5) equation: 



2(3+4x)=7(x-5)

We move all terms to the left:

2(3+4x)-(7(x-5))=0

We add all the numbers together, and all the variables

2(4x+3)-(7(x-5))=0

We multiply parentheses

8x-(7(x-5))+6=0



We calculate terms in parentheses: -(7(x-5)), so:

7(x-5)

We multiply parentheses

7x-35

Back to the equation:

-(7x-35)



We get rid of parentheses

8x-7x+35+6=0

We add all the numbers together, and all the variables

x+41=0

We move all terms containing x to the left, all other terms to the right

x=-41

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