2(3+4x)-2=3-5(x+-1)

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Solution for 2(3+4x)-2=3-5(x+-1) equation:



2(3+4x)-2=3-5(x+-1)
We move all terms to the left:
2(3+4x)-2-(3-5(x+-1))=0
We add all the numbers together, and all the variables
2(4x+3)-(3-5(x-1))-2=0
We multiply parentheses
8x-(3-5(x-1))+6-2=0
We calculate terms in parentheses: -(3-5(x-1)), so:
3-5(x-1)
determiningTheFunctionDomain -5(x-1)+3
We multiply parentheses
-5x+5+3
We add all the numbers together, and all the variables
-5x+8
Back to the equation:
-(-5x+8)
We add all the numbers together, and all the variables
8x-(-5x+8)+4=0
We get rid of parentheses
8x+5x-8+4=0
We add all the numbers together, and all the variables
13x-4=0
We move all terms containing x to the left, all other terms to the right
13x=4
x=4/13
x=4/13

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